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4-y-6y^2=0
We add all the numbers together, and all the variables
-6y^2-1y+4=0
a = -6; b = -1; c = +4;
Δ = b2-4ac
Δ = -12-4·(-6)·4
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{97}}{2*-6}=\frac{1-\sqrt{97}}{-12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{97}}{2*-6}=\frac{1+\sqrt{97}}{-12} $
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